Agas that exerts a pressure of 125.0 mm hg in a container with a volume of ml will exert a pressure of 145 mm hg when transferred to a container with a volume of 0.4650 l.

Boyle's Law states P₁V₁=P₂V₂ so we would rearrange the equation to find V₁ as such: V₁=(P₂V₂)/P₁

Then you would simply plug in the variables that are given as so:
V₁= (145 mmHg x 0.4650 L) / (125.0 mmHg)

As you simplify, you would get: V₁=(67.425 mmHgxL) / (125.0 mmHg)

The final result would be: V₁=0.5394 L

The answer you are seeking is in mL, so a simple conversion would follow and you would get: V₁=539.4 mL.

If significant digits apply, the final, final answer would thus be 539 mL!

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