What mass of xenon tetrafluoride, xef 4 , has the same number of fluorine atoms as 25.0 g of oxygen difluoride, of2?

Answer is: mass of xenon tetrafluoride is 47.98 grams.

1) m(OF₂) = 25.0 g; mass of oxygen difluoride.

n(OF₂) = m(OF₂) ÷ M(OF₂).

n(OF₂) = 25 g ÷ 54 g/mol.

n(OF₂) = 0.462 mol; amount of substance.

In one oxygen difluoride (OF₂) there are two fluorine atoms: n(F) : n(OF₂) = 2 : 1.

n(F) = 0.462 mol · 2.

n(F) = 0.926 mol.

N(F) = n(F) · Na(Avogadro constant).

N(F) = 0.926 mol · 6.022·10²³ 1/mol.

N(F) = 5.576·10²³; number of fluorine atoms in oxygen difluoride.

2) In one molecule of xenon tetrafluoride there are four fluorine atoms:

n(XeF₄) : n(F) = 1 :4.

n(XeF₄) = 0.926 mol ÷ 4.

n(XeF₄) = 0.2315 mol; amount of xenon tetrafluoride.

m(XeF₄) = 0.2315 mol · 207.28 g/mol.

m(XeF₄) = 47.98 g.

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