Gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 21. g of ethane is mixed with 110. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 2 significant digits.

The chemical reaction for this is:

2 C2H6 + 7 O2 => 4 CO2 + 6 H2O

Solving for CO2 with each reactant will give:

21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2 mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O

110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x (18 g H2O/1 mol H2O) = 53.04 g H2O

Since the amount of H2O in C2H6 is lower therefore C2H6 is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)

ANswer:

38 g water

big big big big big   bigbig big big big big big big big big big big big big big big big big big big big big big big big penis

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons