Agraduated cylinder contains 20.5 ml of water. what is the new water level after 35.2 g of silver metal with a density of 10.5 g/ml is submerged in water?

Answer : The volume of new water level in graduated cylinder is 23.85 mL.

Explanation :

To calculate volume of a silver metal, we use the equation:

We are given:

Density of silver metal = 10.5 g/mL

Mass of silver metal = 35.2 g

Putting values in above equation, we get:

Now we have to calculate the volume of new water level in graduated cylinder.

Volume of water in graduated cylinder = 20.5 mL

Volume of silver metal = 3.35 mL

Volume of new water level = Volume of water in graduated cylinder + Volume of silver metal

Volume of new water level = 20.5 mL + 3.35 mL

Volume of new water level = 23.85 mL

Therefore, the volume of new water level in graduated cylinder is 23.85 mL.

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