An experiment produced 0.10 g co2, with a volume of 0.056 l at stp. if the accepted density of co2 at stp is 1.96 g/l, what is the approximate percent error?

The density of CO2 getting from experiment is 0.1/0.056 = 1.79 g/L. The percent error of this is (1.96 -1.79)/1.96*100%=8.67%. So the approximate percent error is 8.67%.

Ithink this is what you meant. the temperature at which a liquid begins to boil is called the boiling point. the boiling point of water is 212°f or 100°c.  and at that point will start to turn into steam (gas)

The air is going to come out because of the low pressure.