You are about to perform some intricate electrical studies on single skeletal muscle fibers from a gastronemius muscle. but first, you must prepare 6l of a 170 mm nacl solution in which to bath the isolated muscle during your studies. how many grams of nacl must you weigh out on the lab balance to prepare this bath solution? (hint: the molecular weight of nacl is 58.44 grams/mole).

I'm quite confused with the given unit for concentration reported as 'mm'. Usually that would just be 'm' for molality or 'M' for molarity. Based on the given data, I think that would be mM which is 1/1000 of M. So, 170 mM is equal to 0.17 M. With that being said, the solution is as follows:

0.17 M = Moles solute/ 6 L
Moles solute = 1.02 moles
Mass of solute = 1.02 moles * 58.44 g/mole = 59.6088 grams NaCl

Only one reactant yields 2 or more products. meaning you will only have 1 product and it will break down into 2 or more products. eg. h2o -> h2 + o2