Given 7.55 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

Explanation:

The balanced reaction will be:

The molecular weight of the ethyl butyrate is:

Atomic weight C = 12

Atomic weight O = 16

Atomic weight H = 1

Molecular weight = (6*12)+(1*12)+(16*2)

Molecular weight = 116

The molecular weight of the butanoic acid is:

Atomic weight C = 12

Atomic weight O = 16

Atomic weight H = 1

Molecular weight = (4*12)+(1*8)+(16*2)

Molecular weight = 88

Finding the mass using stoichiometry:

14 days is the half-life of phosphorus-32