The reaction of ethyl acetate with sodium hydroxide, ch3cooc2h5(aq)+naoh(aq)⇌ch3coona(aq )+c2h5oh(aq) is first order in ch3cooc2h5 and first order in naoh. if the concentration of ch3cooc2h5 was increased by half and the concentration of naoh was quadrupled, by what factor would the reaction rate increase? express your answer numerically.

The reaction rate will increase by a factor of 6

Rate2 = 6(Rate1)

Explanation:

The given reaction is:

k = rate constant

m = order w.r.t to = 1

n = order w.r.t to = 1

Therefore, the initial rate is:

It is given that   is increased by 1/2. Therefore the new concentration =

It is given that the concentration of   was quadrupled. Similarly, new concentration of   is =

Therefore, the new rate is:

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter