Which would be expected to have the higher boiling point, t-butyl alcohol (2-methyl-2-propanol) or n-butyl alcohol (1-butanol)?

I would imagine that n-butanol would have the higher boiling point because it has less branching and therefore stronger intermolecular forces between molecules.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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