A 1.4639-g sample of limestone is analyzed for Fe, Ca, and Mg. The iron is determined as Fe2O3 yielding 0.0357 g. Calcium is isolated as CaSO4, yielding a precipitate of 1.4058 g, and Mg is isolated as 0.0672 g of Mg2P2O7. Report the amount of Fe, Ca, and Mg in the limestone sample as %w/w Fe2O3, %w/w CaO, and %w/w MgO

(2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)-x(x^2-9)^(1/3) (x^2+4)^((-1)/2))/(x^2+4)

The two terms in the numerator are 2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)
and -x(x^2-9)^(1/3) (x^2+4)^((-1)/2)

Dividing the first term with the denominator (x^2+4), you get: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3)

Dividing the second term with the denominator, you get: -x(x^2-9)^(1/3) (x^2+4)^((-3)/2)

So, combining the results(that is adding them), the answer is:
(2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)-x(x^2-9)^(1/3) (x^2+4)^((-1)/2))/(x^2+4)

The two terms in the numerator are 2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)
and -x(x^2-9)^(1/3) (x^2+4)^((-1)/2)

Dividing the first term with the denominator (x^2+4), you get: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3)

Dividing the second term with the denominator, you get: -x(x^2-9)^(1/3) (x^2+4)^((-3)/2)

So, combining the results(that is adding them), the answer is:

What does that mean you dum bum

Decomposition is the cycle at which bacteria breaks down any organic material into the soil