The volume of a gas is 0.668 L at 66.8°C. At what Celsius temperature will the gas have a volume of 0.942 L, assuming the pressure remains constant.

206 c

Explanation:

Use the Charles' Law because you have the volume and temperature given.

V1 / T1 = V2 / T2

Let's list the given:

V1 = 0.668 L

V2 = 0.942 L

T1 = 66.8 C (339.8K)

Convert all Celsius temps to Kelvin. Just add 273.

Asked: T2

Derive the formula for T2.

T2 = V2T1 / V1

    = (0.942)(339.8) / 0.668

    = 479K

Since the temp should be in C, just subtract 273 from 479K.

The answer is 206 C.