Chemistry, 23.04.2021 21:00 ptanner706
The equation for the combustion of methanol is 2CH3OH + 302 =2CO2 + 4H2O. How many liters of carbon dioxide are produced by the combustion of 64.0 g of methanol (CH3OH)?
22.4 L CO.
89.6 L CO2
11.2 L CO2
44.8 L CO.
Answers: 1
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The equation for the combustion of methanol is 2CH3OH + 302 =2CO2 + 4H2O. How many liters of carbon...
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