The decomposition of HI(g) is a second order reaction. 2 HI(g) → I2(g) + H2(g)

Above is some data from an experiment in which HI was decomposed. 

Using the reaction data above:
(a) If you wanted to create a linear graph for this experiment with time on the x-axis, what variable would you put on the y-axis?
(b) Use the data above to calculate k; include units.
(c) How many seconds will it take for the concentration of HI to reach 0.050 M?
(d) What will be the concentration of HI after 50.0 seconds?

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(c) How many seconds will it take for the concentration of HI to reach 0.050 M?

Explanation:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :