The rate of effusion of Xe gas through a porous barrier is observed to be 9.14 x 10-4 mol/h. Under the same conditions, the rate of effusion of Ar gas would be:
mol/h.​

Rate of Ar= 1.65 x mol/h

Explanation:

Here we'll use Graham's Law where

R= rate of effusion and M= molar mass

Let's plug in what we know.

You could switch them where Xe is M1 (on the bottom)  instead of M2, but I find it easier when the unknown is R1, where it acts like a whole number. It makes the algebra part of the equation easier.

Let's solve for R1.

R1= 1.089 x

R1= 1.65 x mol/h