Calculate delta G for the following rxn at 25 degrees celcius. 3Mn2+ (aq) + 2Al(s) -><- 3Mn(s) + 2Al3+ (aq)

The
anode= Mn2+ + 2e- -> Mn
= -1.18 V
The
Cathode= Al3+ + 3e- -> Al
= -1.66 V

The Ecell= -1.66-(-1.18)= -0.48 V

But I do not know how to find Delta G.
Delta G= -nFE

The answer is in kj/mol.
Can anyone help?

i believe it is c.) 1575 j.

that tool would be a compass

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.