Use the following equation to answer the questions that follow. Fe + 2 HCl --> FeCl2 + H2

a. If you have 3.000 moles of HCl, how many moles of gas could you make?

b. If you have 6.132 moles of each reactant, which one will run out first?

c. Based on your answer from (b), how many grams of FeCl2 would you expect to make?

d. How many moles of Excess Reactant reacted based on (b)?

e. How much Excess Reactant is left over, in moles, from (b)?

f. When actually carrying out the experiment with 6.132 moles of each reactant, you make 310.2grams of iron(II) chloride. What is your percent yield?