Consider the gaseous (All reactants and products are gases) equilibrium reaction for the formation of SO3 from SO2 and O2. (Hint: You need to write the balanced chemical equation). When 3.00 moles of SO2 and 3.00 moles of O2 are placed in a 1 L flask and allowed to reach equilibrium at a certain temperature, which one of the following is the correct the equilibrium amount of O2? Given that the equilibrium amount of SO3 is 1.00 mole at the same temperature.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied