Calculate the change in enthalpy, AH, for the reaction: 2H2 (g) + 2C (s, graphite) + O2(g) → HC2H302 (1)
from the following information.
a. HC2H302 (1) + 202 (g) → 2C02(g) + 2H20 (1)
b. C(s, graphite) + O2(g) → CO2 (g)
C. H2(g) + 12 02(g) → H20 (1)
AHa = -875kJ
Днь = -394.51k
AHe= -285.5kJ

Fake and a real . . . . . ..

Reaction involved in present system is :   c12h22o11 + h2o → 2 c6h12o6the reaction system is obeying following rate law:   rate = k[c12h22o11]thus, it is a first order reaction.now, for 1st order reactionrate constant (k) =  given: initial conc. = 3.0 g, final conc. = 2.7 g, t = 2.5 h∴rate constant (k) =  ∴ k = 0.04215 h-1now, for 1st order reaction, half life = 0.693/k = 0.693/0.04215 = 16.4 hthus correct answer is option b