Question 1 2 pts
Lead (II) iodide (a bright yellow solid) is formed according to the following reaction:
2 KI + Pb(NO3)2 --> 2KNO3 + Pbl2
In an experiment, 30.8 g of potassium iodide are placed in a flask. How many grams of lead
(II) iodide would you expect to be produced in this reaction?
Molar Masses:
Kl is 166 g/mole
Pbl2 is 461 g/mole

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