Helium and air are contained in a conduit 7 mm in diameter and 0.08 m long at 44 deg C and 1 atm. The partial pressure of helium at one end of the tube is 0.075 atm and at the other end is 0.03 atm. Calculate the following for steady state equimolar counter diffusion. (a) Molar flux of He, (b) Molar flux of air, and (c) Partial pressure of helium at half way point of the conduit.

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

the answer is 75.0%.