4. Balance the following equation. Then determine the number of mols of Nitrogen formed given the values in a, b and c. NH3 + O2 → N2 + H2O
a. 4 mol NH3

b. 4 mol N2

c. 4.5 mol O2

4NH3 + 3O2 → 2N2 + 6H2O

a. 2 moles

b. 4 moles

c. 3 moles

Explanation:

a. 4 mol NH3

4NH3 + 3O2 → 2N2 + 6H2O

  4      :     3    :    2     :    6

  4                                        (mol)

⇒ = 4 × 2 ÷ 4 = 2

b. 4 mol N2

c. 4.5 mol O2

4NH3 + 3O2 → 2N2 + 6H2O

4      :     3    :    2     :    6

           4.5                          (mol)

⇒ = 4.5 × 2 ÷ 3 = 3

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.