Chemistry, 05.05.2021 19:00 GabbyLandry
Decane (C10H22) can be split into propene (C3H6) and heptane (C7H16) by cracking
. These 3 molecules can all be described as ..
A. alkanes
B. alkenes
C. monomers
D. hydrocarbons
Answers: 2
Chemistry, 22.06.2019 07:40
21. consider the following chemical reaction: n2+ o2 2 no if 10.0 g of n2 reacts with excess oxygen then how many grams of no can be formed? a) 10.7 g b) 21.4 g c) 32.9 g d) 42.8 g page 4 of 8
Answers: 2
Chemistry, 22.06.2019 13:30
An animal cell loses the ability to convert energy stored in food to energy that the cell can use. which of the cell's organelles has stopped working? a.the mitochondria b.the nucleus c.the vacuoles d.the endoplasmic reticulum
Answers: 1
Chemistry, 22.06.2019 20:00
For the reaction c6h14(g) & longrightarrow; c6h6(g) + 4h2(g), δp(h2)/δt was found to be 2.5 x 10-2 atm/s, where δp(h2) is the change in pressure of hydrogen. determine δp(c6h14)/δt for this reaction at the same time.
Answers: 2
Chemistry, 23.06.2019 00:20
Steam reforming of methane ( ch4) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. an industrial chemist studying this reaction fills a 1.5 l flask with 3.5 atm of methane gas and 1.3 atm of water vapor at 43.0°c. he then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of carbon monoxide gas to be 1 .0 atm. calculate the pressure equilibrium constant for the steam reforming of methane at the final temperature of the mixture. round your answer to 2 significant digits.
Answers: 1
Decane (C10H22) can be split into propene (C3H6) and heptane (C7H16) by cracking
. These 3 molecul...
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