You want to make a 0.65M solution of NaOH for a lab. If you need 150.0mL (0.150 L) of this solution, how much NaOH (molar mass = 40.00 g/mol) should you measure out to make the solution ? Answer in grams, 2 s. f.

i think   the answer is c hope i'm right

since electrons are negative the answer is neagtaive

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2