El dióxido de nitrógeno reacciona con agua para producir oxígeno y amoniaco. Con la ecuación de la ley del gas ideal,
calcule los gramos de NH3 que pueden producirse cuando
4.00 L de NO2 reaccionan a una temperatura de 415 °C y una
presión de 725 mmHg.
4NO2(g) + 6H2O(g) 4, 702(8) + 4NH3(g)

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :