A sample was then prepared containing 14.00 mL of coffee and 8.00 mL of 4.80 ppm Li , and diluted to a 50.00 mL total volume. The ratio of the internal standard signal to the analyte signal in the unknown sample was found to be 0.840/1.000 (Li signal/Na signal). Determine the unknown concentration of Na in the coffee sample.

The right answer is "".

Explanation:

The given values are:

According to the question,

The concentration of standard will be:

=  

=  

=  

Coffee after dilution,

⇒  

or,

⇒  

On substituting the values, we get

⇒              

⇒              

⇒              

hence,

In unknown sample, the concentration of coffee will be:

=  

=  

=  

*tilts head* sounds more like a statement