Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of the balloon drops to 250 K, find the volume

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

Substitute the values into the formula.

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

The units of Kelvin cancel, so we are left with the units of mL.

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

The volume of the balloon at 250 K is approximately 416.7 milliliters.

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