A solution was prepared by dissolving 27.1g of sucrose (C12H22O11) in 250 g of water. Find the molality of the solution(molar mass of C12H22O11 is 342.8) -.108 m
-108 m
-317 m
-.317 m

M = 0.317 m

Explanation:

From the given information:

Using the following formula:, the molality M is:

where;

M = molality

= mass of the solute = 27.1 g

= molar mass of the solute = 342.8

= mass of the given solvent  = 250 g

∴

M = 0.317 m

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