Lead (II) Sulfate reacts with sodium iodide in a double displacement reaction. Write out the reaction and balance. There are 18 moles of lead sulfate available and 35 moles of sodium iodide. Answer all of the following: A) Which is the limiting reactant? B) Which is the excess reactant? C) How many moles of excess reactant is left over? D) How many moles of each product can be made?

your picture is not part of the scientific method.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8