g The following equation is given for the dissociation of the complex ion Ag(NH3) 2. The dissociation constant, Kd, is the equilibrium constant for the dissociation of a complex ion into its component ions. What would be the expression for the dissociation constant of Ag(NH3) 2.

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Explanation:

Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.

Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)

The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

The dissociation constant for this reaction is:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.

i think its 100

i hope this !