A gas has a volume of 62.65 L at stp. At what temperture in C would the volume of the gas be 78.31 at a pressure of 612 mm hg

1.79°C

Explanation:

Applying,

PV/T = P'V'/T' Equation 1

Where P = Initial presssure, V = Initial volume, T = Initial temperature, P' = Final pressure, V' = Final volume, T' = Final Temperature.

make T' the subject of the equation

T' = P'V'T/PV Equation 2

From the question,

Given: P = 760 mmHg (Standard pressure), T = 273 K (Standard temperature), V = 62.65 L, P' = 612 mmHg, V' = 78.31

Substitute these values into equation 2

T' = (612×78.31×273)/(760×62.65)

T' = 274.79 K

T' = (274.79-273) °C

T' = 1.79°C

your answers are a,b,,e and f

i hope this

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.