3. 7moles of Ba(NO3)2 is dissolved in 75kg of distilled water. What is the boiling point of this solution? Hint: Find molality first.

100.14°C

Explanation:

The boling point elevation is a colligative property that describes the increasing in boiling point of a solution regard to the boiling point of the pure solvent. The equation is:

ΔT = Kf*m*i

Where ΔT is boiling point elevation

Kf is boiling point elevation (0.51°C/m for water)

m is molality of the solution (7moles Ba(NO3)2 / 75kg = 0.09333m

i is Van't Hoff factor = 3 for Ba(NO3)2 (Because its dissolution produce 3 ions = Ba²⁺ and 2 NO₃⁻

Replacing:

ΔT = 0.51°C/m*0.09333m*3

ΔT = 0.14°C is the boiling point elevation

As the boiling point of water is 100°C, the boiling point of the solution is:

100°C + 0.14°C =

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.