What is the pOH of a 0.013 M Ca(OH)2 solution?

1.59

Explanation: For every mol of Ca(OH)2 there are two moles of OH so the concentration of OH is .013 x2 =.026 M OH

pOH = - log [OH] so -log .026 = 1.59

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

indium, and thallium have three electrons i think