How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

0.6 L

Explanation:

As this problem deals with a dilution process, we can solve it by using the following formula:

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the diluted solution's. That means that in this case:

We input the data:

And solve for V₂:

Finally we convert 600 mL to L:

b. th3 n4zc4 pl4t3 15 c0nv3rg1ng w1th the s0uth 4m3ric4n pl4t3.

the answer for sodium is 0.186

the answer for rubidium is 0.251