A 4.70 g nugget of pure gold absorbed 279 J of heat. The initial temperature was 29.0°C. What was the final temperature?

Final temperature = 489.17°C

Explanation:

Given - A 4.70 g nugget of pure gold absorbed 279 J of heat. The initial temperature was 29.0°C.

To find - What was the final temperature ?

Proof -

Given that,

q = 279 J

m = 4.70 g

We know that, C = 0.129 J

Also,

We know the specific heat equation that,

q = m(ΔT)C

⇒ΔT = q ÷ mc

        = 279 ÷ (4.70)(0.129)

        = 279 ÷ 0.6063

        = 460.17°C

⇒ΔT = 460.17°C

Now,

We know that,

Change in Temperature is the difference of final and initial Temperature

So,

ΔT = Final temp. - Initial Temp.

⇒460.17°C = Final Temp. - 29.0°C

⇒Final temperature = 460.17°C + 29.0°C

                                 = 489.17°C

⇒Final temperature = 489.17°C

answer: mole of the gas

answer: mole of the gasexplanation: