2Fe +3S= Fe2S3 how many grams of sulfur are involved in this reaction if 95 grams of iron are needed to react with sulfur

83 g

Explanation:

Step 1: Write the balanced equation

2 Fe + 3 S ⇒ Fe₂S₃

Step 2: Calculate the moles corresponding to 95 g of Fe

The molar mass of Fe is 55.85 g/mol.

95 g × 1 mol/55.85 g = 1.7 mol

Step 3: Calculate the moles of S needed to react with 1.7 moles of Fe

The molar ratio of Fe to S is 2:3. The moles of S needed are 3/2 × 1.7 mol = 2.6 mol

Step 4: Calculate the mass corresponding to 2.6 moles of S

The molar mass of S is 32.07 g/mol.

2.6 mol × 32.07 g/mol = 83 g

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

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