Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride and oxygen. What is the balanced equation for this reaction? When counting atoms in parentheses, multiply all subscripts by the number outside the parentheses to get the number of atoms. BaCl3(s) + O2(g) → BaCl(s) + Cl2(g) + O2(g)

2BaOCl3(s) → 2BaCl(s) + Cl2(g) + O2(g)

Ba(ClO3)2(s) → BaCl2(s) + O2(g)

Ba(ClO3)2(s) → BaCl2(s) + 3O2(g)

2Ba(ClO3)2(s) → BaCl(s) + 6O2(g)

Ba(ClO)2(s) → BaCl2(s) + O2(g)

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Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.