Write the alpha decay equation for the following isotope: 22788/Ra

Explanation:

During an alpha decay, the mass number of the parent nucleus decreases by four units while the atomic number of the parent nucleus decreases by two units.

Hence the mass number of the daughter nucleus is four units less than that of the parent while the atomic number of the daughter nucleus is two units less than that of the parent.

Hence the alpha decay equation for 227/88 Ra is shown in the answer box.

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