A 50.5 L flask contains 3.25 mol of an unknown gas at 288.6 K, what is the pressure of
this gas?

1.52atm is the pressure of the gas

Explanation:

To solve this question we must use the general gas law:

PV = nRT

Where P is pressure in atm = Our incognite

V is volume = 50.5L

n are moles of gas = 3.25moles

R is gas constat = 0.082atmL/molK

And T is absolute temperature = 288.6K

To solve pressure:

P = nRT / V

P = 3.25mol*0.082atmL/molK*288.6K / 50.5L

P = 1.52atm is the pressure of the gas

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