Chemistry, 18.05.2021 14:00 fireemblam101ovu1gt
Calculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid water at 65.0 °C.
Answers: 3
![Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]](/tpl/images/1330/5123/31632.png)
(1)
- Mass of the ice, in kilograms.
- Specific heat of ice, in kilojoules per kilogram-degree Celsius.
- Specific heat of water, in kilojoules per kilogram-degree Celsius.
- Latent heat of fusion, in kilojoules per degree Celsius. 
- Initial temperature of water, in degrees Celsius.
- Fusion point of water, in degrees Celsius.
- Final temperature of water, in degree Celsius.
- Total energy absorbed, in kilojoules.
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, then the total energy absorbed is:![Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right]](/tpl/images/1330/5123/d15d0.png)
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Calculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid w...
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