2NACIO3 (s) → 2NaCl (s) + 302 (g) 53 grams of NaClO3 will produce how many grams of NaCl?
(Molar Mass: NaClO3 = 106g, NaCl = 58g and O2 = 329)

We begin with a balanced chemical equation that is provided in the question.

2NaClO

3

→2NaCl+3O

2

We have 80.0 grams of Oxygen and we want grams of Sodium Chloride.

We set up a roadmap to solve the problem

gramsO

2

→molO

2

→molNaCl→gramsNaCl

we need the molar mass (gm) of O

2

and NaCl

O

2

=31.98 g/mol and NaCl = 58.44 g / mol

we need the mole ratio between O

2

:NaCl

3:2 This comes from the coefficients of the balanced chemical equation.

Now we set up conversion factors following the roadmap from above.

Unit we want in the numerator, unit to cancel in the denominator.

80.0gO

2

×

31.98gO

2

1molO

2

×

3molO

2

2molNaCl

×

1molNaCl

58.44gNaCl

Multiply the numerators, and divide the denominators.

97.5gNaCl will be produced with 80.0 grams O

2