Chemistry, 18.05.2021 20:40 rosetoheart2
Una cantidad de 1.208 g de un metal M (masa molar = 25.0 g/mol) liberó 0.281 L de hidrógeno molecular
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la ecuación correspondiente y escriba las fórmulas del óxido y del sulfato de M
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Una cantidad de 1.208 g de un metal M (masa molar = 25.0 g/mol) liberó 0.281 L de hidrógeno molecula...
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