Will Mark Brainliest. 1. Analysis of a hydrate of iron(III) chloride revealed that in a 10.00g sample of hydrate, 6.00 g is anhydrous iron(III) chloride and 4.00 g is water. Determine the formula and the name of the hydrate.

FeCl₃ . 6H₂O, BRAINLIST PLZ

Explanation:

1) The chemical formula of iron(III) chloride is FeCl₃ (the oxidation number of Fe is 3+, and the oxidation number of Cl is 1-).

2) The formula that you are lookin for the hydrate is of the type FeCl₃ . n H₂O, where n is the number of water molecules per each unit formula of Fe₂O₃.

3) Find the mass of anhydrous FeCl₃ by difference:

mass of FeCl₃ = mass of the sample - mass of the water in the sample

mass of FeCl₃ = 5.49g - 2.20 g = 3.29 g

4) Convert the mass of FeCl₃ in number of moles

number of moles = mass in grams / molar mass

molar mass of FeCl₃ = 55.845 g/mol + 3×35.453 g/mol = 162.204 g/mol

number of moles = 3.29 g / 162.204 g/mol = 0.0203 mol FeCl₃

5) Convert the mass of water in number of moles:

molar mass of water = 18.015 g/mol

number of moles of water = mass in grams / molar mass = 2.20 g / 18.015 g/mol = 0.122 moles H₂O

6) Find the mole ratio of water to iron chloride:

0.122 mol water / 0.0203 mol iron chloride = 6.01 ≈ 6

Therefore, the complete formula of the hydrate is FeCl₃ . 6H₂O,

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