A bowl containing 150 grams of water, is heated from 25 °C to 100 °C. The specific heat of water is 4.184 J/g°C. How much heat energy is required to heat the water?

4.7 × 10⁴ J

Explanation:

Step 1: Given data

Step 2: Calculate the temperature change (ΔT)

ΔT = 100 °C - 25 °C = 75 °C

Step 3: Calculate the heat required (Q) to raise the temperature of the water

We will use the following expression.

Q = c × m × ΔT

Q = 4.184 J/g.°C × 150 g × 75 °C = 4.7 × 10⁴ J