A silver bar with a specific heat of 0.235J/gºC has a mass of 250.g and is heated from 22.0°C to 68.5°C. How much heat will the silver bar absorb?​

2731.875 J

Explanation:

Applying

Q = cm(t₂-t₁) Equation 1

Where Q = amount of heat, c = specific heat capacity of silver, m = mass of silver, t₂ = Final temperature of silver, t₁ = Initial temperature of silver

From the question,

Given: c = 0.235 J/g°C, m = 250 g, t₁ = 22.0°C, t₂ = 68.5°C

Substitute these values into equation 1

Q = 0.235×250(68.5-22.0)

Q = 58.75(46.5)

Q = 2731.875 J

answer; i believe the correct answer is (solid gold);