What is the pressure of gas at 496 Liters and 200 Kelvin if the original pressure was 0.250 atm. at 300 liters and 400 kelvin?

0.076 atm

Explanation:

Using the combined gas law formula;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

V1 = initial volume (L)

V2 = final volume (L)

According to the information provided in this question;

P2 = ?

P1 = 0.250 atm

V2 = 496 L

V1 = 300 L

T2 = 200K

T1 = 400K

Using P1V1/T1 = P2V2/T2

0.250 × 300/400 = P2 × 496/200

75/400 = 496 P2/200

0.1875 = 2.48P2

P2 = 0.1875 ÷ 2.48

P2 = 0.076 atm

3 hours because it is a decent distance.

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