2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) (balanced) When 52 grams of chlorine gas react, the actual yield is 42.5 grams, what is the

percent yield?

Percent yield = 65.2 %

Explanation:

The reaction determines this:

2 moles of Al react to 3 moles of chlorine gas in order to produce 2 mol of aluminum chloride.

We determine the moles of chlorine:

52 g . 1mol /70.9g = 0.733 moles of Cl₂

3 moles of gas can produce 2 moles of salt

Then, our 0.733 moles may produce (0.733 . 2) / 3 = 0.489 moles of AlCl₃

We convert moles to mass to predict the 100 % yield

0.489 mol . 133.3 g /mol = 65.19 g

Percent yield = (Yield produced / 100 % yield) . 100

Percent yield = (42.5 g / 65.19g) . 100 = 65.2 %

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

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