subject
Chemistry, 20.05.2021 07:20 brainguy124

A 2.36-gram sample of NaHCO, was completely decomposed in an experiment. 2NaHCO3-Na2CO, + H2CO3
In this experiment carbon dioxide and water vapors combine to form H2CO3. After decomposition the Na2C0s had a mass of 1.57 grams.
A. Determine the mass of the H2CO, produced
B. Calculate the percentage yield of H. CO, for the reaction. Show your work or describe the calculation process in detail.

ansver
Answers: 3

Another question on Chemistry

question
Chemistry, 22.06.2019 06:30
Over the last 90 years, scientists have added to the body of evidence supporting the big bang theory. what is the latest piece of evidence discovered in 2014?
Answers: 1
question
Chemistry, 22.06.2019 07:00
The boiling point of propanoic acid is higher than that of 1-butanol because: propanoic acid has a higher molecular weight than 1-butanol. propanoic acid is more soluble in water than 1-butanol. propanoic acid is a better hydrogen bond donor than 1-butanol. propanoic acid forms hydrogen bonded dimers and 1-butanol does not. 1-butanol forms hydrogen bonded dimers and propanoic acid does not.
Answers: 2
question
Chemistry, 22.06.2019 12:30
Word equation for k(s)+h2o(l) yield koh(aq) + h2(g)
Answers: 1
question
Chemistry, 23.06.2019 00:00
(04.05 hc) analyze the given diagram of the carbon cycle below. part 1: which compound does c represent? part 2: name a process that could release this compound into the air. part 3: explain how the elements that form it are conserved during the carbon cycle. use complete sentences to explain your answer. justify how this compound was created from a recycling of carbon in the carbon cycle. use complete sentences to explain your answer.
Answers: 3
You know the right answer?
A 2.36-gram sample of NaHCO, was completely decomposed in an experiment. 2NaHCO3-Na2CO, + H2CO3
Questions
question
Mathematics, 11.11.2020 01:00
question
Mathematics, 11.11.2020 01:00
question
Mathematics, 11.11.2020 01:00
question
Chemistry, 11.11.2020 01:00
question
History, 11.11.2020 01:00
Questions on the website: 13722367