How many grams of CO are needed to produce 209.7 g Fe?

Fe2O3+3CO⟶3CO2+2Fe

157.8 g

Explanation:

Step 1: Write the balanced equation

Fe₂O₃ + 3 CO ⟶ 3 CO₂ + 2 Fe

Step 2: Calculate the moles corresponding to 209.7 g of Fe

The molar mass of Fe is 55.85 g/mol

209.7 g × 1 mol/55.85 g = 3.755 mol

Step 3: Calculate the moles of CO needed to produce 3.755 moles of Fe

The molar ratio of CO to Fe is 3:2. The moles of CO needed are 3/2 × 3.755 = 5.633 mol

Step 4: Calculate the mass corresponding to 5.633 moles of CO

The molar mass of CO is 28.01 g/mol.

5.633 mol × 28.01 g/mol = 157.8 g