For the decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C , the average rate of disappearance of N2O5 over the time period from t = 0 min to t = 112 min is found to be 5.80×10^-4 M min^-1. The average rate of formation of O2 over the same time period is: M min-1

1.45 × 10⁻³ M min⁻¹

Explanation:

Step 1: Write the balanced reaction for the decomposition of dinitrogen pentoxide

2 N₂O₅(g) ⇒ 2 N₂(g) + 5 O₂(g)

Step 2: Calculate the average rate of formation of oxygen

The average rate of disappearance of N₂O₅ over the time period from t = 0 min to t = 112 min is found to be 5.80 × 10⁻⁴ M min⁻¹ (5.80 × 10⁻⁴ molN₂O₅ L⁻¹  min⁻¹). Given that the molar ratio of N₂O₅ to O₂ is 2:5, the average rate of formation of O₂ is:

5.80 × 10⁻⁴ molN₂O₅ L⁻¹  min⁻¹ × 5 molO₂/ 2 molN₂O₅ = 1.45 × 10⁻³ molO₂ L⁻¹  min⁻¹ = 1.45 × 10⁻³ M min⁻¹

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.