Please help I need ASAP thanks 25.0mL of 0.350M HCl(aq) is titrated to the endpoint with 0.535 M KOH(aq).
a. Calculate the volume of KOH used. Show your work.
b. Would the answer to this question be different if Ba(OH), were used? Explain
why or why not.

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally